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Disproportionation of Sn(II){CH(SiMe 3 ) 2 } 2 to ˙Sn(III){CH(SiMe 3 ) 2 } 3 and ˙Sn(I){CH(SiMe 3 ) 2 }: characterization of the Sn(I) product.

Kristian L MearsBronson RuizGia-Ann NguyenWenxing ZouJames C FettingerPhilip P Power
Published in: Chemical communications (Cambridge, England) (2023)
Half a century after the photolytic disproportionation of Lappert's dialkyl stannylene SnR 2 , R = CH(SiMe 3 ) 2 (1) gave the persistent trivalent radical [˙SnR 3 ], the characterization of the corresponding Sn(I) product, ˙SnR is now described. It was isolated as the hexastannaprismane Sn 6 R 6 (2), from the reduction of 1 by the Mg(I)-reagent, Mg(BDI Dip ) 2 (BDI = (DipNCMe) 2 CH, Dip = 2,6-diisopropylphenyl).
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